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A rectangle has perimeter 40. Quantity A: The maximum possible area of the rectangle. Quantity B: 105.

GRE · 2025 · quant slot 1
Question:
A rectangle has perimeter 40. Quantity A: The maximum possible area of the rectangle. Quantity B: 105.

Options

(A) Quantity A is greater
(B) Quantity B is greater
(C) The two quantities are equal
(D) The relationship cannot be determined
Answer: (B) Quantity B is greater

Explanation:
Perimeter = 40 ⇒ l + w = 20. Area is maximized when l = w = 10 (square). Max area = 100 < 105 → Quantity B greater.

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