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If -3 < 2x + 1 < 9, what is the range of possible values for x?

GRE Β· 2023 Β· quant slot 2
Question:
If -3 < 2x + 1 < 9, what is the range of possible values for x?

Options

(A) -2 < x < 4
(B) -1 < x < 5
(C) 0 < x < 4
(D) -2 < x < 5
(E) -1 < x < 4
Answer: (A) -2 < x < 4

Explanation:
Solve the compound inequality: -3 < 2x + 1 gives -4 < 2x, so x > -2. Also, 2x + 1 < 9 gives 2x < 8, so x < 4. Therefore -2 < x < 4.

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