These are sample practice MCQs created for exam preparation. These are NOT official exam questions.
A solution is 20% alcohol. How many liters of pure alcohol must be added to 10 liters of this solution to make it 40% alcohol?
Question:
A solution is 20% alcohol. How many liters of pure alcohol must be added to 10 liters of this solution to make it 40% alcohol?
A solution is 20% alcohol. How many liters of pure alcohol must be added to 10 liters of this solution to make it 40% alcohol?
Options
Answer: (D) 3.33 liters
Explanation:
Initial alcohol = 0.20 × 10 = 2 liters. Let x = liters of pure alcohol added. Then (2 + x)/(10 + x) = 0.40. Solving: 2 + x = 4 + 0.4x, so 0.6x = 2, giving x = 3.33 liters.
Explanation:
Initial alcohol = 0.20 × 10 = 2 liters. Let x = liters of pure alcohol added. Then (2 + x)/(10 + x) = 0.40. Solving: 2 + x = 4 + 0.4x, so 0.6x = 2, giving x = 3.33 liters.
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