These are sample practice MCQs created for exam preparation. These are NOT official exam questions.
If n = 2^a × 3^b × 5^c, where a, b, and c are positive integers, how many distinct factors does n have if a = 3, b = 2, and c = 1?
Question:
If n = 2^a × 3^b × 5^c, where a, b, and c are positive integers, how many distinct factors does n have if a = 3, b = 2, and c = 1?
If n = 2^a × 3^b × 5^c, where a, b, and c are positive integers, how many distinct factors does n have if a = 3, b = 2, and c = 1?
Options
Answer: (C) 24
Explanation:
Number of factors = (a + 1)(b + 1)(c + 1) = (3 + 1)(2 + 1)(1 + 1) = 4 × 3 × 2 = 24.
Explanation:
Number of factors = (a + 1)(b + 1)(c + 1) = (3 + 1)(2 + 1)(1 + 1) = 4 × 3 × 2 = 24.
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