A regular octagon ABCDEFGH has sides of length 6 cm each. Then the area, in sq. cm , of the square ACEG is
Question:
A regular octagon ABCDEFGH has sides of length 6 cm each. Then the area, in sq. cm , of the square ACEG is
A regular octagon ABCDEFGH has sides of length 6 cm each. Then the area, in sq. cm , of the square ACEG is
Options
Answer: 36(2+2√2)
Explanation:
Step 1: Interior angle of a regular octagon Formula: Interior angle = ((n−2)/n) × 180° n = 8 → ((8−2)/8) × 180° = (6/8) × 180° = 135° Step 2: Area of square ACEG Let side length = 6 cm → a = 6 In ΔBAC (triangle formed by consecutive vertices), use cosine rule to find diagonal: c² = a² + b² − 2ab cos C c² = 6² + 6² − 2·6·6·cos135° c² = 36 + 36 − 72 × (−√2/2) c² = 72 + 36√2 c = √[72 + 36√2] Area of square ACEG = (diagonal)² / 2 = c² / 2 = 36(2 + √2)
Explanation:
Step 1: Interior angle of a regular octagon Formula: Interior angle = ((n−2)/n) × 180° n = 8 → ((8−2)/8) × 180° = (6/8) × 180° = 135° Step 2: Area of square ACEG Let side length = 6 cm → a = 6 In ΔBAC (triangle formed by consecutive vertices), use cosine rule to find diagonal: c² = a² + b² − 2ab cos C c² = 6² + 6² − 2·6·6·cos135° c² = 36 + 36 − 72 × (−√2/2) c² = 72 + 36√2 c = √[72 + 36√2] Area of square ACEG = (diagonal)² / 2 = c² / 2 = 36(2 + √2)
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