The sum of all real values of k for which (18)^k × (1/32768)^(1/3) = 18 × (1/32768)^(1/k), is
Question:
The sum of all real values of k for which (18)^k × (1/32768)^(1/3) = 18 × (1/32768)^(1/k), is
The sum of all real values of k for which (18)^k × (1/32768)^(1/3) = 18 × (1/32768)^(1/k), is
Options
Answer: -2/3
Explanation:
Equation: (1/8)^k × (1/32768)^(1/3) = (1/8) × (1/32768)^(1/k) Step 1: Express as powers of 2: 1/8 = 2⁻³, 1/32768 = 2⁻¹⁵ → 2^(−3k) × 2^(−15/3) = 2^(−3) × 2^(−15/k) → 2^(−3k − 5) = 2^(−3 − 15/k) Step 2: Equate exponents: −3k − 5 = −3 − 15/k → 3k² + 2k − 15 = 0 Step 3: Sum of roots of quadratic = −b/a = −2/3
Explanation:
Equation: (1/8)^k × (1/32768)^(1/3) = (1/8) × (1/32768)^(1/k) Step 1: Express as powers of 2: 1/8 = 2⁻³, 1/32768 = 2⁻¹⁵ → 2^(−3k) × 2^(−15/3) = 2^(−3) × 2^(−15/k) → 2^(−3k − 5) = 2^(−3 − 15/k) Step 2: Equate exponents: −3k − 5 = −3 − 15/k → 3k² + 2k − 15 = 0 Step 3: Sum of roots of quadratic = −b/a = −2/3
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