Renu would take 15 days working 4 hours per day to complete a certain task whereas Seema would take 8 days working 5 hours per day to complete the same task. They decide to work together to complete this task. Seema agrees to work for double the number of hours per day as Renu, while Renu agrees to work for double the number of days as Seema. If Renu works 2 hours per day, then the number of days Seema will work, is
Question:
Renu would take 15 days working 4 hours per day to complete a certain task whereas Seema would take 8 days working 5 hours per day to complete the same task. They decide to work together to complete this task. Seema agrees to work for double the number of hours per day as Renu, while Renu agrees to work for double the number of days as Seema. If Renu works 2 hours per day, then the number of days Seema will work, is
Renu would take 15 days working 4 hours per day to complete a certain task whereas Seema would take 8 days working 5 hours per day to complete the same task. They decide to work together to complete this task. Seema agrees to work for double the number of hours per day as Renu, while Renu agrees to work for double the number of days as Seema. If Renu works 2 hours per day, then the number of days Seema will work, is
Options
Answer: 6
Explanation:
Step 1: Find total work in “man-hours” Renu: 15 days × 4 hours/day = 60 hours Seema: 8 days × 5 hours/day = 40 hours So, total work = 60 “Renu-hours” = 40 “Seema-hours”. Renu’s 1-hour rate: 1/60 of the task per hour Seema’s 1-hour rate: 1/40 of the task per hour Step 2: Define their work schedule Given: Renu works 2 hours/day Seema works double Renu’s hours/day → 4 hours/day Renu works double Seema’s number of days → let Seema work x days → Renu works 2x days Step 3: Work done by each Renu: 2 hours/day × 2x days = 4x hours Seema: 4 hours/day × x days = 4x hours Convert to fraction of task: Renu: (4x / 60) = x/15 Seema: (4x / 40) = x/10 Total work done together = x/15 + x/10 = (2x + 3x)/30 = 5x/30 = x/6 Set total work = 1 → x/6 = 1 → x = 6 ✅ Step 4: Answer Seema works 6 days
Explanation:
Step 1: Find total work in “man-hours” Renu: 15 days × 4 hours/day = 60 hours Seema: 8 days × 5 hours/day = 40 hours So, total work = 60 “Renu-hours” = 40 “Seema-hours”. Renu’s 1-hour rate: 1/60 of the task per hour Seema’s 1-hour rate: 1/40 of the task per hour Step 2: Define their work schedule Given: Renu works 2 hours/day Seema works double Renu’s hours/day → 4 hours/day Renu works double Seema’s number of days → let Seema work x days → Renu works 2x days Step 3: Work done by each Renu: 2 hours/day × 2x days = 4x hours Seema: 4 hours/day × x days = 4x hours Convert to fraction of task: Renu: (4x / 60) = x/15 Seema: (4x / 40) = x/10 Total work done together = x/15 + x/10 = (2x + 3x)/30 = 5x/30 = x/6 Set total work = 1 → x/6 = 1 → x = 6 ✅ Step 4: Answer Seema works 6 days
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