2π
Inequality: −4 ≤ x² + y² + 4(x − y) ≤ 0 Complete the square: (x + 2)² + (y − 2)² − 8 → 4 ≤ (x + 2)² + (y − 2)² ≤ 8 Circular annulus centered at (−2, 2), inner radius 2, outer radius 2√2 Line y ≥ x + 4 passes through the center → region above line = half annulus Annulus area = π*(2√2)² − π*2² = 8π − 4π = 4π Half area = 4π / 2 = 2π Answer: 2π