Let △ABC be an isosceles triangle such that AB and AC are of equal length. AD is the altitude from A on BC and BE is the altitude from B on AC. If AD and BE intersect at O such that ∠AOB=105°, then AD/BE equals:
Question:
Let △ABC be an isosceles triangle such that AB and AC are of equal length. AD is the altitude from A on BC and BE is the altitude from B on AC. If AD and BE intersect at O such that ∠AOB=105°, then AD/BE equals:
Let △ABC be an isosceles triangle such that AB and AC are of equal length. AD is the altitude from A on BC and BE is the altitude from B on AC. If AD and BE intersect at O such that ∠AOB=105°, then AD/BE equals:
Options
Answer: 2cos15°
Explanation:
In isosceles triangle with AB = AC, using properties of altitudes and the given angle, we can establish that AD/BE = 2cos15° through trigonometric relationships involving the orthocenter.
Explanation:
In isosceles triangle with AB = AC, using properties of altitudes and the given angle, we can establish that AD/BE = 2cos15° through trigonometric relationships involving the orthocenter.
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