In a regular polygon, any interior angle exceeds the exterior angle by 120 degrees. Then, the number of diagonals of this polygon is:
Question:
In a regular polygon, any interior angle exceeds the exterior angle by 120 degrees. Then, the number of diagonals of this polygon is:
In a regular polygon, any interior angle exceeds the exterior angle by 120 degrees. Then, the number of diagonals of this polygon is:
Options
Answer: 54
Explanation:
Solution: Step 1: Let the polygon have n sides Interior angle = (n−2) × 180 / n Exterior angle = 360 / n Given: interior − exterior = 120 → ((n−2) × 180 / n) − (360 / n) = 120 Simplify: (180n − 720)/n = 120 → 180 − 720/n = 120 → 720/n = 60 → n = 12 Step 2: Number of diagonals = n(n−3)/2 = 12 × 9 / 2 = 54 Answer: 54
Explanation:
Solution: Step 1: Let the polygon have n sides Interior angle = (n−2) × 180 / n Exterior angle = 360 / n Given: interior − exterior = 120 → ((n−2) × 180 / n) − (360 / n) = 120 Simplify: (180n − 720)/n = 120 → 180 − 720/n = 120 → 720/n = 60 → n = 12 Step 2: Number of diagonals = n(n−3)/2 = 12 × 9 / 2 = 54 Answer: 54
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