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In a company, 20% of the employees work in the manufacturing department. If the total salary obtained by all the manufacturing employees is one-sixth of the total salary obtained by all the employees in the company, then the ratio of the average salary obtained by the manufacturing employees to the average salary obtained by the non-manufacturing employees is:

CAT · 2023 · Quant Slot 2
Question:
In a company, 20% of the employees work in the manufacturing department. If the total salary obtained by all the manufacturing employees is one-sixth of the total salary obtained by all the employees in the company, then the ratio of the average salary obtained by the manufacturing employees to the average salary obtained by the non-manufacturing employees is:

Options

4:5
5:6
5:4
6:5
Answer: 4:5

Explanation:
Step 1: Let total number of employees = 100 Employees in manufacturing (M) = 20% of 100 = 20 Employees in non-manufacturing (N) = 100 − 20 = 80 Step 2: Let total salaries Total salary of all employees = S Total salary of manufacturing employees = S_M = (1/6) S Total salary of non-manufacturing employees = S_N = S − S_M = S − (1/6)S = (5/6)S Step 3: Find average salaries Average salary of manufacturing employees: Avg 𝑀 = 𝑆 𝑀 / 20 = ( 1 / 6 ) 𝑆 / 20 = 𝑆 / 120 Avg M ​ =S M ​ /20=(1/6)S/20=S/120 Average salary of non-manufacturing employees: Avg 𝑁 = 𝑆 𝑁 / 80 = ( 5 / 6 ) 𝑆 / 80 = ( 5 𝑆 ) / ( 480 ) = 𝑆 / 96 Avg N ​ =S N ​ /80=(5/6)S/80=(5S)/(480)=S/96 Step 4: Ratio of average salaries Avg 𝑀 : Avg 𝑁 = ( 𝑆 / 120 ) : ( 𝑆 / 96 ) = 1 / 120 : 1 / 96 = 96 : 120 = 4 : 5 Avg M ​ :Avg N ​ =(S/120):(S/96)=1/120:1/96=96:120=4:5 ✅ Answer 4 : 5

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