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Any non-zero real numbers x, y such that y≠3 and x/y < (x+3)/(y−3), will satisfy the condition:

CAT · 2023 · Quant Slot 2
Question:
Any non-zero real numbers x, y such that y≠3 and x/y < (x+3)/(y−3), will satisfy the condition:

Options

If y>10, then −x>y
If x<0, then −x<y
If y<0, then −x<y
x/y < y/x
Answer: If y<0, then −x<y

Explanation:
Cross multiply the inequality considering the sign of (y−3). Simplify to get −3x < 3y, which gives −x < y. This holds when y<0 based on the inequality constraints.

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