The salaries of three friends Sita, Gita and Mita are initially in the ratio 5:6:7, respectively. In the first year, they get salary hikes of 20%, 25% and 20%, respectively. In the second year, Sita and Mita get salary hikes of 40% and 25%, respectively, and the salary of Gita becomes equal to the mean salary of the three friends. The salary hike of Gita in the second year is
Question:
The salaries of three friends Sita, Gita and Mita are initially in the ratio 5:6:7, respectively. In the first year, they get salary hikes of 20%, 25% and 20%, respectively. In the second year, Sita and Mita get salary hikes of 40% and 25%, respectively, and the salary of Gita becomes equal to the mean salary of the three friends. The salary hike of Gita in the second year is
The salaries of three friends Sita, Gita and Mita are initially in the ratio 5:6:7, respectively. In the first year, they get salary hikes of 20%, 25% and 20%, respectively. In the second year, Sita and Mita get salary hikes of 40% and 25%, respectively, and the salary of Gita becomes equal to the mean salary of the three friends. The salary hike of Gita in the second year is
Options
Answer: 26%
Explanation:
Initial salaries: 5k, 6k, 7k. After year 1: 6k, 7.5k, 8.4k. After year 2: Sita=8.4k, Mita=10.5k, Gita=7.5k(1+x). Mean=(8.4k+7.5k(1+x)+10.5k)/3. Setting Gita equal to mean and solving: 7.5k(1+x)=(18.9k+7.5kx)/3, so 22.5k+22.5kx=18.9k+7.5kx, giving 15kx=3.6k-18.9k. Solving gives x≈0.26 or 26%.
Explanation:
Initial salaries: 5k, 6k, 7k. After year 1: 6k, 7.5k, 8.4k. After year 2: Sita=8.4k, Mita=10.5k, Gita=7.5k(1+x). Mean=(8.4k+7.5k(1+x)+10.5k)/3. Setting Gita equal to mean and solving: 7.5k(1+x)=(18.9k+7.5kx)/3, so 22.5k+22.5kx=18.9k+7.5kx, giving 15kx=3.6k-18.9k. Solving gives x≈0.26 or 26%.
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