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If x and y are positive real numbers such that log_x(x^2+12)=4 and 3log_y(x)=1, then x+y equals

CAT · 2023 · Quant Slot 1
Question:
If x and y are positive real numbers such that log_x(x^2+12)=4 and 3log_y(x)=1, then x+y equals

Options

20
11
68
10
Answer: 10

Explanation:
From log_x(x^2 + 12) = 4 we get x^4 = x^2 + 12. Let t = x^2. Then t^2 - t - 12 = 0 → (t - 4)(t + 3) = 0. Since t > 0, t = 4, so x^2 = 4 → x = 2 (positive). From 3·log_y(x) = 1 we get log_y(x) = 1/3, so y^(1/3) = x → y = x^3. With x = 2, y = 8. Therefore x + y = 2 + 8 = 10. So the correct option is 10.

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