Two cars travel from different locations at constant speeds. To meet each other after starting at the same time, they take 1.5 hours if they travel towards each other, but 10.5 hours if they travel in the same direction. If the speed of the slower car is 60 km/hr, then the distance traveled, in km, by the slower car when it meets the other car while traveling towards each other, is:
Question:
Two cars travel from different locations at constant speeds. To meet each other after starting at the same time, they take 1.5 hours if they travel towards each other, but 10.5 hours if they travel in the same direction. If the speed of the slower car is 60 km/hr, then the distance traveled, in km, by the slower car when it meets the other car while traveling towards each other, is:
Two cars travel from different locations at constant speeds. To meet each other after starting at the same time, they take 1.5 hours if they travel towards each other, but 10.5 hours if they travel in the same direction. If the speed of the slower car is 60 km/hr, then the distance traveled, in km, by the slower car when it meets the other car while traveling towards each other, is:
Options
Answer: 90
Explanation:
Let speeds be v₁=60 km/hr (slower) and v₂. When traveling towards each other: (v₁+v₂)×1.5 = d. When traveling same direction: (v₂-v₁)×10.5 = d. Solving: v₂ = 100 km/hr. Distance by slower car = 60×1.5 = 90 km.
Explanation:
Let speeds be v₁=60 km/hr (slower) and v₂. When traveling towards each other: (v₁+v₂)×1.5 = d. When traveling same direction: (v₂-v₁)×10.5 = d. Solving: v₂ = 100 km/hr. Distance by slower car = 60×1.5 = 90 km.
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