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Two ships meet mid-ocean, and then, one ship goes south and the other ship goes west, both travelling at constant speeds. Two hours later, they are 60 km apart. If the speed of one of the ships is 6 km per hour more than the other one, then the speed, in km per hour, of the slower ship is

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Question:
Two ships meet mid-ocean, and then, one ship goes south and the other ship goes west, both travelling at constant speeds. Two hours later, they are 60 km apart. If the speed of one of the ships is 6 km per hour more than the other one, then the speed, in km per hour, of the slower ship is

Options

(1) 12

(2) 18

(3) 20

(4) 24

Answer: (2) 18

Explanation:
Let slower ship speed = v km/h, faster = v+6 km/h. After 2 hours, distances are 2v and 2(v+6). Using Pythagorean theorem: (2v)²+(2(v+6))²=60². Simplifying: 4v²+4(v²+12v+36)=3600, giving 8v²+48v+144=3600, so v²+6v-432=0. Solving: v=18 km/h.

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Two ships meet mid-ocean, and then, one ship goes south and the other ship goes west, both travelling at constant speeds. Two hours later, they are 60 km apart. If the speed of one of the ships is 6 km per hour more than the other one, then the speed, in km per hour, of the slower ship is

Options

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Two ships meet mid-ocean, and then, one ship goes south and the other ship goes west, both travelling at constant speeds. Two hours later, they are 60 km apart. If the speed of one of the ships is 6 km per hour more than the other one, then the speed, in km per hour, of the slower ship is

Options

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