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Let r and c be real numbers. If r and -r are roots of 5x³+cx²-10x+9=0, then c equals

CAT · 2022 · Quant Slot 2
Question:
Let r and c be real numbers. If r and -r are roots of 5x³+cx²-10x+9=0, then c equals

Options

(1) -9/2
(2) 9/2
(3) -4
(4) 4
Answer: (1) -9/2

Explanation:
Given: r and -r are roots of the cubic equation 5x^3 + c x^2 - 10x + 9 = 0 Since r and -r are roots, x^2 - r^2 is a factor. So write: 5x^3 + c x^2 - 10x + 9 = (x^2 - r^2)(5x + k) for some real number k. Expand the right-hand side: (x^2 - r^2)(5x + k) = 5x^3 + k x^2 - 5 r^2 x - k r^2 Compare coefficients with the original equation: From the x-term: -5 r^2 = -10 → r^2 = 2 From the constant term: -k r^2 = 9 → -k * 2 = 9 → k = -9/2 Since k is the coefficient of x^2, we have c = k = -9/2 Answer: -9/2

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