For some natural number n, assume that (15,000)! is divisible by (n!)!. The largest possible value of n is
Question:
For some natural number n, assume that (15,000)! is divisible by (n!)!. The largest possible value of n is
For some natural number n, assume that (15,000)! is divisible by (n!)!. The largest possible value of n is
Options
Answer: (2) 7
Explanation:
Step 1: Translate the problem We want (n!)! to divide 15,000!. For k! to divide m!, we must have k ≤ m. Here, (n!)! is the factorial of n!. So we need: (n!)! ≤ 15,000! We are looking for the largest n such that this inequality holds. Step 2: Approximate using factorial growth Factorials grow rapidly. Recall: k! grows very fast with k, so (n!)! ≤ 15,000! implies n! ≤ 15,000 Step 3: Find largest n with n! ≤ 15,000 n = 5 → 5! = 120 ≤ 15,000 ✅ n = 6 → 6! = 720 ≤ 15,000 ✅ n = 7 → 7! = 5040 ≤ 15,000 ✅ n = 8 → 8! = 40,320 > 15,000 ❌ So the largest n satisfying n! ≤ 15,000 is n = 7. Answer: 7
Explanation:
Step 1: Translate the problem We want (n!)! to divide 15,000!. For k! to divide m!, we must have k ≤ m. Here, (n!)! is the factorial of n!. So we need: (n!)! ≤ 15,000! We are looking for the largest n such that this inequality holds. Step 2: Approximate using factorial growth Factorials grow rapidly. Recall: k! grows very fast with k, so (n!)! ≤ 15,000! implies n! ≤ 15,000 Step 3: Find largest n with n! ≤ 15,000 n = 5 → 5! = 120 ≤ 15,000 ✅ n = 6 → 6! = 720 ≤ 15,000 ✅ n = 7 → 7! = 5040 ≤ 15,000 ✅ n = 8 → 8! = 40,320 > 15,000 ❌ So the largest n satisfying n! ≤ 15,000 is n = 7. Answer: 7
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