Pinky is standing in a queue at a ticket counter. Suppose the ratio of the number of persons standing ahead of Pinky to the number of persons standing behind her in the queue is 3 : 5. If the total number of persons in the queue is less than 300, then the maximum possible number of persons standing ahead of Pinky is
Options
- 99
- 111
- 100
- none
Correct Answer
111
Explanation
Let the number of persons ahead = 3k and behind = 5k.
Total people = 3k + 5k + 1 = 8k + 1 < 300
⇒ 8k ≤ 298 ⇒ k ≤ 37.25 ⇒ k_max = 37
Maximum persons ahead = 3 × 37 = 111.
← More CAT PYQs